Suppose the complete integral is
f(x,y,z,a,b)=0.(4)
To obtain a general integral, we may put
b=b(a), where
b is an arbitrary function of
a. Then we consider the envelope of the one-parameter family
f(x,y,z,a,b(a))=0.(5)
The envelope condition is
fa(x,y,z,a,b(a))+fb(x,y,z,a,b(a))b′(a)=0.(6)
Equations (5) and (6) together describe the general integral.