BMLabs Mathematics
REPOSITORY
Integral Surface and Tangent Plane Interpretation
BMLABS MATHEMATICS REPOSITORY
mathematics.bmlabs.co.in
Author
Dr. Bivash Majumder
Assistant Professor in Mathematics
Prabhat Kumar College, Contai
REPOSITORY
BMLABS MATHEMATICS REPOSITORY
mathematics.bmlabs.co.in
Author
Dr. Bivash Majumder
Assistant Professor in Mathematics
Prabhat Kumar College, Contai
REPOSITORY
BMLABS MATHEMATICS REPOSITORY
mathematics.bmlabs.co.in
Author
Dr. Bivash Majumder
Assistant Professor in Mathematics
Prabhat Kumar College, Contai
Published
15 May 2026
Dynamic Sandbox
Dynamic Sandbox
Dynamic Sandbox
Because every value of $u$ corresponds to a point $(x,y,u)$ in three-dimensional space. So the graph of $u=u(x,y)$ is a surface.
For an implicit surface $f(x,y,u)=0$, the gradient vector points in the normal direction to the surface.
It says that the vector $(a,b,c)$ lies in the tangent plane of the integral surface.
It prepares the method of characteristics, where we follow curves whose tangent direction is given by $(a,b,c)$.
Semilinear First-Order Partial Differential Equations