:::section[The Unit Hyperbola]
Circular functions parametrize
X2+Y2=1. Hyperbolic functions play the analogous role for the right-hand branch of
X2−Y2=1.
:::
:::theorem[Parametrization of the Unit Hyperbola]
For every
t∈R, the point
(cosht,sinht)
lies on the unit hyperbola
X2−Y2=1.
:::
:::proof[Proof]
Let
X=cosht and
Y=sinht. Using the fundamental identity,
X2−Y2=cosh2t−sinh2t=1.
Moreover,
X=cosht≥1, so this parametrization traces the right-hand branch.
□
:::
:::remark[Hyperbolic and Circular Parametrizations]
The point
(cost,sint) lies on the unit circle, while
(cosht,sinht) lies on the unit hyperbola. The names “circular” and “hyperbolic” record these geometric roles.
:::
:::theorem[Monotonicity and Symmetry]
The function
sinhx is strictly increasing on
R. The function
coshx is even, strictly decreasing on
(−∞,0], and strictly increasing on
[0,∞).
For every
x∈R,
coshx−sinhx=e−x>0.
:::
:::proof[Proof]
Let
h>0. By the addition identities,
sinh(x+h)−sinhx=2sinh(2h)cosh(x+2h)>0.
Hence
sinh is strictly increasing. For
0≤x<y,
coshy−coshx=2sinh(2x+y)sinh(2y−x)>0.
Thus
cosh is strictly increasing on
[0,∞). Its evenness gives the decreasing behavior on
(−∞,0]. The last inequality follows from the exponential identity above.
□
:::
:::key-formula[Domains and Ranges]
Dom(sinh)Dom(cosh)Dom(tanh)Dom(sech)Dom(coth)Dom(csch)=R,=R,=R,=R,=R∖{0},=R∖{0},Ran(sinh)Ran(cosh)Ran(tanh)Ran(sech)Ran(coth)Ran(csch)=R,=[1,∞),=(−1,1),=(0,1],=(−∞,−1)∪(1,∞),=R∖{0}.
:::
:::example[Reading a Range from an Identity]
Since
sechx=1/coshx and
coshx≥1, one has
0<sechx≤1.
The value
1 occurs at
x=0, while the value
0 is approached but never attained.
:::
:::exercise[Practice Questions]
1. Verify that
(cosh(ln2),sinh(ln2)) lies on
X2−Y2=1.
2. Explain why the range of
tanhx excludes
±1.
3. Determine all real
x for which
coshx=1.
4. Use symmetry to describe the two branches of
cothx.
:::
:::answer[Answers and Guidance]
1. The point is
(5/4,3/4), and
25/16−9/16=1.
2. Since
tanhx=e2x+1e2x−1,
its value is strictly between
−1 and
1 for finite
x.
3. Only
x=0, because
coshx≥1 with equality only there.
4.
coth is odd; one branch has values greater than
1 for
x>0, and the reflected branch has values less than
−1 for
x<0.
:::
:::faq[Frequently Asked Questions]
Q: Does
(cosht,sinht) cover both branches of the unit hyperbola?
A: No. Since
cosht≥1, it covers the right-hand branch only.
Q: Why is zero excluded from the range of
sech?
A: A reciprocal of the finite positive number
coshx cannot be zero, although it tends to zero as
∣x∣ grows.
Q: Is
coshx>sinhx still true when
x is negative?
A: Yes. Their difference is
e−x, which is positive for every real
x.
:::
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:::