Metric Spaces
Comprehensive module covering 5 sections in Functional Analysis.
REPOSITORY
BMLABS MATHEMATICS REPOSITORY
mathematics.bmlabs.co.in
Author
Dr. Bivash Majumder
Assistant Professor in Mathematics
Prabhat Kumar College, Contai
Functional Analysis · Metric Spaces
Prove completeness of finite-dimensional spaces, summable sequence spaces, bounded sequences, and function spaces.
Understand the central mathematical ideas of Completeness of Standard Metric Spaces.
Interpret the principal results and their mathematical conditions.
Follow and justify the main proof strategy step by step.
Practise the concept independently and verify the result.
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4 concepts
12 guided steps
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Definitions
5
Theorems
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Lemmas
1
Corollaries
6
Proofs
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Examples
1
Exercises
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Local progress
Lesson profile
theorem
Let and let for . Then is complete.
corollary
The space with the maximum metric is complete.
theorem
Let and let with metric . Then is complete.
theorem
The space of all bounded scalar sequences with metric is complete.
theorem
Let be the set of bounded scalar-valued functions on a nonempty set with the uniform metric. Then is complete.
theorem
Let with the uniform metric. Then is complete.
introductory
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Completeness of Standard Metric Spaces Concept Map. 19 concepts.
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Definitions
12
Results
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Applications
2
Practice
2 practice items
Many standard spaces used in analysis are complete. The proofs follow a common pattern: begin with a Cauchy sequence in the metric, extract coordinatewise or pointwise candidate limits, prove that the candidate belongs to the same space, and finally prove convergence in the original metric. This lesson records the main completeness results needed later.
Let and let for . Then is complete.
Given that with metric . To prove that is complete. Let be Cauchy and write . Since
each coordinate sequence is Cauchy in . Let and . Finite coordinate convergence gives . Hence is complete.
The space with the maximum metric is complete.
Given that is Cauchy in . To prove that it converges. Each coordinate sequence is Cauchy in and hence converges. Since there are finitely many coordinates, convergence is in the maximum metric. Hence the maximum metric space is complete.
Let and let with metric . Then is complete.
Given that . To prove that is complete. Let be a Cauchy sequence, where . Each fixed coordinate sequence is Cauchy, so define . The Cauchy condition gives uniform control of tails, which shows and . Hence is complete.
The space of all bounded scalar sequences with metric is complete.
Given a Cauchy sequence of bounded sequences. To prove that it converges in the supremum metric. Coordinatewise limits define a sequence . A fixed Cauchy comparison term shows that is bounded. The Cauchy condition then passes to the coordinatewise limit and gives . Hence the bounded sequence space is complete.
Let be the set of bounded scalar-valued functions on a nonempty set with the uniform metric. Then is complete.
Given a Cauchy sequence in . To prove that it converges in . For each , the scalar sequence is Cauchy. Define . A fixed comparison function shows that is bounded. Passing the Cauchy estimate to the pointwise limit gives uniform convergence . Hence is complete.
Let with the uniform metric. Then is complete.
Given a Cauchy sequence in . To prove that it converges in . It converges uniformly to a bounded function by completeness of bounded functions. Since the uniform limit of continuous functions is continuous, the limit belongs to . Hence is complete.
[1] Why do Cauchy sequences in give Cauchy coordinate sequences? [2] State the completeness theorem for . [3] Why is complete under the uniform metric?
[1] Each coordinate difference is bounded above by the metric distance. [2] is complete under the uniform metric. [3] Uniform limits of continuous functions are continuous.
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Next, compare coordinatewise, pointwise, and uniform convergence.