## Explicit and Related-Variable Functions
### Worked Example: Composite Trigonometric–Exponential Function
Find
dx2d2y
when
y=tan(e3x).
### Worked Example: Velocity as a Function of Position
If
v=dtdx,
show that
dtdv=vdxdv=dt2d2x.
## Implicit Functions
### Formula: First Derivative of a General Conic
If
ax2+2hxy+by2+2gx+2fy+c=0,
then
dxdy=−hx+by+fax+hy+g.
### Worked Example: Second Derivative of a General Conic
If
ax2+2hxy+by2+2gx+2fy+c=0,
prove that
dx2d2y=(hx+by+f)3abc+2fgh−af2−bg2−ch2.
## Parametric Functions
### Formula: Second Derivative in Parametric Form
Let
x=ϕ(t),y=ψ(t).
If the suffixes denote differentiation with respect to
t, then
dx2d2y=x13x1y2−x2y1.
### Worked Example: Parametric Second Derivative
Let
x=ϕ(t),y=ψ(t).
Show that
dx2d2y=x13x1y2−x2y1.
Hence obtain
dx2d2y when
x=a(cosθ+θsinθ),y=a(sinθ−θcosθ).
## Functions of Functions and Inverse Functions
### Formula: Second Derivative of a Composite Function
Let
y=f(u) and
u=g(x). Then
dx2d2y=dx2d2ududy+(dxdu)2du2d2y.
### Worked Example: Composite-Function Second Derivative
Let
y=f(u) and
u=g(x) be differentiable functions. Prove that
dx2d2y=dx2d2ududy+(dxdu)2du2d2y.
### Formula: Second Derivative of an Inverse Function
dy2d2x=−(dxdy)3dx2d2y.
### Formula: Third Derivative of an Inverse Function
dy3d3x=−(dxdy)5dx3d3ydxdy−3(dx2d2y)2.
### Worked Example: Higher Derivatives of an Inverse Function
Starting from
dydx=dy/dx1,
obtain formulas for
dy2d2x and
dy3d3x.
### Worked Example: Second Derivative of a Pedal-Type Function
If
p2=a2cos2θ+b2sin2θ,
prove that
p+dθ2d2p=p3a2b2.
:::section[Method and Verification]
State the domain, select the appropriate derivative formula, carry out the differentiation chronologically, and verify the result by checking a low order or differentiating once more.
:::
:::exercise[Practice Questions]
1. Find
d2y/dx2 for
y=tan(e3x).
2. If
v=dx/dt, prove that
d2x/dt2=vdv/dx wherever
v is differentiable as a function of
x.
3. For
x=t2+1 and
y=t3−t, calculate
d2y/dx2 at
t=1.
:::
:::answer[Answers and Solution Guidance]
1. With
u=e3x,
y′=3usec2u and
y′′=9usec2u+18u2sec2utanu.
2.
dv/dt=(dv/dx)(dx/dt)=vdv/dx, and
dv/dt=d2x/dt2.
3.
dy/dx=(3t2−1)/(2t) and
d2y/dx2=(3t2+1)/(4t3), so the value at
t=1 is
1.
:::
:::faq[Frequently Asked Questions]
Q: What is the central method in second-order differentiation?
A: The method is to identify the applicable formula or decomposition, state its hypotheses, and then carry out the derivative calculation in the required order.
Q: How should a general nth-derivative formula be verified?
A: Check one or two initial orders and differentiate the proposed expression once to confirm the formula with
n replaced by
n+1.
Q: Which restrictions must be recorded?
A: Record every domain condition, excluded denominator value, differentiability requirement, and index restriction used by the formula.
:::
:::call-to-action[Continue Learning]
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