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    Vidyasagar University UG Previous Year Question Papers
    B.Sc. Mathematics Honours Question Papers – CBCS | Vidyasagar University
    B.Sc. Mathematics Honours Question Papers 2019 (CBCS)
    B.Sc. Mathematics Honours C-1 Question Paper 2019 (CBCS)

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    Vidyasagar University UG Previous Year Question Papers
    B.Sc. Mathematics Honours Question Papers 2017 (CBCS)
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    B.Sc. Mathematics Honours Question Papers 2019 (CBCS)
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    B.Sc. Mathematics Honours C-1 Question Paper 2019 (CBCS)

    Learning Objectives
    • • Master derivations of B.Sc. Mathematics Honours C-1 Question Paper 2019 (CBCS).
    • • Bridge theoretical limits with practice.

    Calculus, Geometry and Differential Equations (C1-T)

    B.Sc./1st Sem (H)/MATH/23 (CBCS)
    2019
    1st Semester Examination
    MATHEMATICS (Honours)
    Paper: C1-T
    [Calculus, Geometry and Differential Equation]
    [CBCS]

    Full Marks: 60 Time: 3 Hours

    Unit - I

    1. Answer any three of the following questions: 3×2=63 \times 2 = 63×2=6
    (a) If y=eaxcos⁡2bxy = e^{ax} \cos^{2} bxy=eaxcos2bx, find yn(a,b>0)y_{n} (a, b > 0)yn​(a,b>0).
    (b) Find the oblique asymptotes of the curve y=3x2log⁡(e−13x)y = \frac{3x}{2} \log (e - \frac{1}{3x})y=23x​log(e−3x1​).
    (c) If y=xn−1log⁡xy = x^{n-1} \log xy=xn−1logx then prove that yn=(n−1)!xy_{n} = \frac{(n-1)!}{x}yn​=x(n−1)!​.
    (d) What is reciprocal spiral? Sketch it.
    (e) The parabolic path is given by y=xtan⁡θ−x24hcos⁡2θy = x \tan \theta - \frac{x^{2}}{4h \cos^{2} \theta}y=xtanθ−4hcos2θx2​, what will be the asymptote of parabolic paths? 2. Answer any one question: 1×10=101 \times 10 = 101×10=10
    (a) (i) Find the evolute of the ellipse x2a2+y2b2=1\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1a2x2​+b2y2​=1.
    (ii) Let Pn=Dn(xnlog⁡x)P_{n} = D^{n}(x^{n} \log x)Pn​=Dn(xnlogx). Prove that Pn=nPn−1+(n−1)!P_{n} = nP_{n-1} + (n-1)!Pn​=nPn−1​+(n−1)!. Hence show that Pn=n!(log⁡x+1+12+⋯+1n)P_{n} = n! (\log x + 1 + \frac{1}{2} + \dots + \frac{1}{n})Pn​=n!(logx+1+21​+⋯+n1​).
    (b) (i) Prove that the envelope of circles whose centres lie on the rectangular hyperbola xy=c2xy = c^{2}xy=c2 and which pass through its centre is (x2+y2)2=16c2xy(x^{2} + y^{2})^{2} = 16c^{2}xy(x2+y2)2=16c2xy.
    (ii) Find the point of inflexion on the curve (θ2−1)r=aθ2(\theta^{2} - 1)r = a\theta^{2}(θ2−1)r=aθ2.

    Unit - II

    3. Answer any two questions: 2×2=42 \times 2 = 42×2=4
    (a) If In=∫0π/2cos⁡n−2xsin⁡xdx,n>2I_{n} = \int_{0}^{\pi/2} \cos^{n-2} x \sin x dx, n > 2In​=∫0π/2​cosn−2xsinxdx,n>2 Prove that 2(n−1)In=1+(n−2)In−12(n-1)I_{n} = 1 + (n-2)I_{n-1}2(n−1)In​=1+(n−2)In−1​.
    (b) Find the length of the curve x=eθsin⁡θx = e^{\theta} \sin \thetax=eθsinθ and y=eθcos⁡θy = e^{\theta} \cos \thetay=eθcosθ between θ=0\theta = 0θ=0 to θ=π2\theta = \frac{\pi}{2}θ=2π​.
    (c) Find the reduction formula for ∫cos⁡nxsin⁡(nx)dx\int \cos^{n} x \sin (nx) dx∫cosnxsin(nx)dx. 4. Answer any two questions: 2×5=102 \times 5 = 102×5=10
    (a) Prove that the volume of the solid obtained by revolving the lemniscate r2=a2cos⁡2θr^{2} = a^{2} \cos 2\thetar2=a2cos2θ about the initial line is 12πa3{12log⁡(2+1)−13}\frac{1}{2} \pi a^{3} \{ \frac{1}{\sqrt{2}} \log (\sqrt{2} + 1) - \frac{1}{3} \}21​πa3{2​1​log(2​+1)−31​}.
    (b) If Im,n=∫01xm(1−x)ndxI_{m,n} = \int_{0}^{1} x^{m} (1 - x)^{n} dxIm,n​=∫01​xm(1−x)ndx, where mmm and nnn are positive integers, then prove that (m+n+1)Im,n=nIm,n−1(m + n + 1)I_{m,n} = nI_{m,n-1}(m+n+1)Im,n​=nIm,n−1​ and deduce that Im,n=m!n!(m+n+1)!I_{m,n} = \frac{m!n!}{(m + n + 1)!}Im,n​=(m+n+1)!m!n!​.
    (c) Evaluate the surface area of the solid generated by revolving the cycloid x=a(θ−sin⁡θ)x = a(\theta - \sin \theta)x=a(θ−sinθ), y=a(1−cos⁡θ)y = a(1 - \cos \theta)y=a(1−cosθ) about the line y=0y = 0y=0.

    Unit - III

    5. Answer any three questions: 3×2=63 \times 2 = 63×2=6
    (a) Find the centre and foci of the conic x2−2y2−2x+8y−1=0x^{2} - 2y^{2} - 2x + 8y - 1 = 0x2−2y2−2x+8y−1=0.
    (b) Find the equation of the sphere of which the circle x2+y2+z2+2x−2y+4z−3=0,2x+y+z=4x^{2} + y^{2} + z^{2} + 2x - 2y + 4z - 3 = 0, 2x + y + z = 4x2+y2+z2+2x−2y+4z−3=0,2x+y+z=4 is a great circle.
    (c) Find the condition that the line lr=Acos⁡θ+Bsin⁡θ\frac{l}{r} = A \cos \theta + B \sin \thetarl​=Acosθ+Bsinθ may touch the conic lr=1−ecos⁡θ\frac{l}{r} = 1 - e \cos \thetarl​=1−ecosθ.
    (d) For what angle must the axes be turned to remove the term xyxyxy from 7x2+4xy+3y2=07x^{2} + 4xy + 3y^{2} = 07x2+4xy+3y2=0.
    (e) Find the equation of cone whose vertex is origin and the base curve is x2+y2=4,z=2x^{2} + y^{2} = 4, z = 2x2+y2=4,z=2. 6. Answer any one question: 1×5=51 \times 5 = 51×5=5
    (a) If rrr be the radius of the circle x2+y2+z2+2ux+2vy+2wz+d=0,lx+my+nz=0x^{2} + y^{2} + z^{2} + 2ux + 2vy + 2wz + d = 0, lx + my + nz = 0x2+y2+z2+2ux+2vy+2wz+d=0,lx+my+nz=0 then prove that (r2+d)(l2+m2+n2)=(mw−nv)2+(nu−lw)2+(lv−mu)2(r^{2} + d)(l^{2} + m^{2} + n^{2}) = (mw - nv)^{2} + (nu - lw)^{2} + (lv - mu)^{2}(r2+d)(l2+m2+n2)=(mw−nv)2+(nu−lw)2+(lv−mu)2.
    (b) Show that the feet of the normals from the point (α,β,γ)(\alpha, \beta, \gamma)(α,β,γ) to the ellipsoid x2a2+y2b2+z2c2=1\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} + \frac{z^{2}}{c^{2}} = 1a2x2​+b2y2​+c2z2​=1 lie on the intersection of the ellipsoid and cone αa2(b2−c2)x+βb2(c2−a2)y+γc2(a2−b2)z=0\frac{\alpha a^{2} (b^{2} - c^{2})}{x} + \frac{\beta b^{2} (c^{2} - a^{2})}{y} + \frac{\gamma c^{2} (a^{2} - b^{2})}{z} = 0xαa2(b2−c2)​+yβb2(c2−a2)​+zγc2(a2−b2)​=0. 7. Answer any one question: 1×10=101 \times 10 = 101×10=10
    (a) (i) Show that the plane 3x−2y−z=03x - 2y - z = 03x−2y−z=0 cuts the cones 21x2−4y2−5z2=021x^{2} - 4y^{2} - 5z^{2} = 021x2−4y2−5z2=0 and 3yz−2zx+2xy=03yz - 2zx + 2xy = 03yz−2zx+2xy=0 in the same pair of perpendicular lines.
    (ii) Find the equation of the cylinder, whose generators are parallel to the straight line x2=y3=z5\frac{x}{2} = \frac{y}{3} = \frac{z}{5}2x​=3y​=5z​ and which passes through the conic z=0,3x2+7y2=12z = 0, 3x^{2} + 7y^{2} = 12z=0,3x2+7y2=12.
    (b) (i) Find the locus of the point of intersection of the perpendicular generators of the hyperboloid x2a2+y2b2−z2c2=1\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} - \frac{z^{2}}{c^{2}} = 1a2x2​+b2y2​−c2z2​=1.
    (ii) Reduce the equation x2+3y2+3z2−2xy−2yz−2zx+1=0x^{2} + 3y^{2} + 3z^{2} - 2xy - 2yz - 2zx + 1 = 0x2+3y2+3z2−2xy−2yz−2zx+1=0 to its canonical form and determine the type of quadratic represented by it.

    Unit - IV

    8. Answer any two questions: 2×2=42 \times 2 = 42×2=4
    (a) Find the integrating factor of the differential equation (2xy+3x2y+6y3)dx+(x2+6y2)dy=0(2xy + 3x^{2}y + 6y^{3})dx + (x^{2} + 6y^{2})dy = 0(2xy+3x2y+6y3)dx+(x2+6y2)dy=0.
    (b) Show that the general solution of the equation dydx+Py=Q\frac{dy}{dx} + Py = Qdxdy​+Py=Q can be written in the form y=k(u−v)+vy = k(u - v) + vy=k(u−v)+v, where kkk is a constant and uuu and vvv are its two particular solutions.
    (c) Solve: dydx+ycos⁡x=xyn\frac{dy}{dx} + y \cos x = xy^{n}dxdy​+ycosx=xyn. 9. Answer any one question: 1×5=51 \times 5 = 51×5=5
    (a) The population of a country increases at the rate proportional to the number of inhabitants. If the population doubles in 30 years, in how many years will it triple?
    (b) Solve: (px2+y2)(px+y)=(p+1)2(px^{2} + y^{2})(px + y) = (p + 1)^{2}(px2+y2)(px+y)=(p+1)2 by using the transformation u=xy,v=x+yu = xy, v = x + yu=xy,v=x+y, where p=dydxp = \frac{dy}{dx}p=dxdy​.
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    B.Sc. Mathematics Honours Question Papers – CBCS | Vidyasagar University